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Joule's Law

 Joule’s Rules Essay

JOULE'S LAW

Advantages and analysis question

In this experiment, we were going to investigate the amount of resistance R associated with an immersion water heater. We had to make our own heaters, and measure the resistance by using a multimeter. Then we had to measure the current I, using an ammeter and a voltmeter. And at last, there were to determine the electrical power P of the immersion heaters. This experiment would require to make a desk with the data collection, a graph, and some calculations applying Joule's and Ohms law. Our study question is: How can we all prove Joule's law?

Experiment procedure

Initially build an immersion water heater with a wire joints and wires. The heater consists of an around 25 cm twisted kanthal wire. Place the line around a pencil for a slinky effect. Tighten up the screws to assure the wires will be fastened. To look for the power L of the immersion heater, fill half of a plastic cup with regular tap water (must be able to cover the wire), and warmth it along with your immersion water heater. By measuring the heat of water as a function of time, and draw a graph, you can calculate the power P. The heater is usually lowered in the water and is connected to a great AC power supply (alternating current). At the same time employing an ammeter and analog voltmeter, measure the current I throughout the resistor as well as the pad. Evaluate for your five – twelve min. Make a desk and a graph. Equipment

Data collection

Our initial investigation was going to measure the level of resistance of the concentration heater by using a multimeter. The resistance was measured to:

R sama dengan 0, 73 О©

Following, we had to look for the power L of the immersion heater through the use of water heating. The method was explained inside the experiment procedure. First we measured the current I throughout the resistor applying an ammeter and a voltmeter. The measured beliefs are:

We = 4, 8 A

p. m. = 3, 5 Sixth is v

The outcomes of our try things out are displayed in the stand below. Mass of the water: 175, forty seven g (amount of water) – 6, 3 g (plastic cup) = 169, 17 g Time (min. )| 0| 1| 2| 3| 4| 5| 6| 7| almost 8...

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